Base | Representation |
---|---|
bin | 10010111011101011100… |
… | …101001100111011010000 |
3 | 11121101012012012222100101 |
4 | 102323223211030323100 |
5 | 132304003311141144 |
6 | 2433404110102144 |
7 | 162665540652046 |
oct | 22735345147320 |
9 | 4541165188311 |
10 | 1301032521424 |
11 | 461845a38889 |
12 | 1901951aa954 |
13 | 958c0cb016c |
14 | 46d82760396 |
15 | 23c998cc6d4 |
hex | 12eeb94ced0 |
1301032521424 has 10 divisors (see below), whose sum is σ = 2520750510290. Its totient is φ = 650516260704.
The previous prime is 1301032521421. The next prime is 1301032521491. The reversal of 1301032521424 is 4241252301031.
It can be written as a sum of positive squares in only one way, i.e., 713234299024 + 587798222400 = 844532^2 + 766680^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1301032521392 and 1301032521401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1301032521421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40657266279 + ... + 40657266310.
It is an arithmetic number, because the mean of its divisors is an integer number (252075051029).
Almost surely, 21301032521424 is an apocalyptic number.
It is an amenable number.
1301032521424 is a deficient number, since it is larger than the sum of its proper divisors (1219717988866).
1301032521424 is an equidigital number, since it uses as much as digits as its factorization.
1301032521424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81314532597 (or 81314532591 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1301032521424 its reverse (4241252301031), we get a palindrome (5542284822455).
The spelling of 1301032521424 in words is "one trillion, three hundred one billion, thirty-two million, five hundred twenty-one thousand, four hundred twenty-four".
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