13010353535551 has 4 divisors (see below), whose sum is σ = 13010360971672. Its totient is φ = 13010346099432.

The previous prime is 13010353535479. The next prime is 13010353535561. The reversal of 13010353535551 is 15553535301031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13010353535551 - 2²⁵ = 13010319981119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13010353535561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 506020 + ... + 5126086.

It is an arithmetic number, because the mean of its divisors is an integer number (3252590242918).

Almost surely, 2^{13010353535551} is an apocalyptic number.

13010353535551 is a deficient number, since it is larger than the sum of its proper divisors (7436121).

13010353535551 is an equidigital number, since it uses as much as digits as its factorization.

13010353535551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7436120.

The product of its (nonzero) digits is 253125, while the sum is 40.

Adding to 13010353535551 its reverse (15553535301031), we get a palindrome (28563888836582).

The spelling of 13010353535551 in words is "thirteen trillion, ten billion, three hundred fifty-three million, five hundred thirty-five thousand, five hundred fifty-one".