1301041044133 has 4 divisors (see below), whose sum is σ = 1301169730048. Its totient is φ = 1300912358220.

The previous prime is 1301041044019. The next prime is 1301041044169. The reversal of 1301041044133 is 3314401401031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301041044133 - 2¹⁷ = 1301040913061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301041044098 and 1301041044107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301041144133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64327791 + ... + 64348012.

It is an arithmetic number, because the mean of its divisors is an integer number (325292432512).

Almost surely, 2^{1301041044133} is an apocalyptic number.

It is an amenable number.

1301041044133 is a deficient number, since it is larger than the sum of its proper divisors (128685915).

1301041044133 is a wasteful number, since it uses less digits than its factorization.

1301041044133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128685914.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1301041044133 its reverse (3314401401031), we get a palindrome (4615442445164).

The spelling of 1301041044133 in words is "one trillion, three hundred one billion, forty-one million, forty-four thousand, one hundred thirty-three".