13011001213031 has 4 divisors (see below), whose sum is σ = 13011008556000. Its totient is φ = 13010993870064.

The previous prime is 13011001212977. The next prime is 13011001213043. The reversal of 13011001213031 is 13031210011031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13011001213031 is a prime.

It is a super-2 number, since 2×13011001213031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011001213631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808715 + ... + 5164883.

It is an arithmetic number, because the mean of its divisors is an integer number (3252752139000).

Almost surely, 2^{13011001213031} is an apocalyptic number.

13011001213031 is a deficient number, since it is larger than the sum of its proper divisors (7342969).

13011001213031 is an equidigital number, since it uses as much as digits as its factorization.

13011001213031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7342968.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13011001213031 its reverse (13031210011031), we get a palindrome (26042211224062).

The spelling of 13011001213031 in words is "thirteen trillion, eleven billion, one million, two hundred thirteen thousand, thirty-one".