Base | Representation |
---|---|
bin | 111100100101100101… |
… | …0101001011101010101 |
3 | 110102211121002222020222 |
4 | 1321023022221131111 |
5 | 4112431141220313 |
6 | 135434411004125 |
7 | 12254151420332 |
oct | 1711312513525 |
9 | 412747088228 |
10 | 130110101333 |
11 | 501a783a973 |
12 | 21271739645 |
13 | c366944054 |
14 | 6423d69989 |
15 | 35b7861208 |
hex | 1e4b2a9755 |
130110101333 has 4 divisors (see below), whose sum is σ = 134307201408. Its totient is φ = 125913001260.
The previous prime is 130110101309. The next prime is 130110101371. The reversal of 130110101333 is 333101011031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130110101333 - 220 = 130109052757 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130110101533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2098549991 + ... + 2098550052.
It is an arithmetic number, because the mean of its divisors is an integer number (33576800352).
Almost surely, 2130110101333 is an apocalyptic number.
It is an amenable number.
130110101333 is a deficient number, since it is larger than the sum of its proper divisors (4197100075).
130110101333 is an equidigital number, since it uses as much as digits as its factorization.
130110101333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4197100074.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 130110101333 its reverse (333101011031), we get a palindrome (463211112364).
The spelling of 130110101333 in words is "one hundred thirty billion, one hundred ten million, one hundred one thousand, three hundred thirty-three".
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