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13011013333200 = 24352109540718397
BaseRepresentation
bin1011110101010101110011…
…0100111111000011010000
31201001211200220000211020010
42331111130310333003100
53201133023403130300
643401102122314520
72512005016365501
oct275253464770320
951054626024203
1013011013333200
114166a37914a63
121561756058a40
13734c195a081c
1432da449a6ba8
151786a64aba50
hexbd55cd3f0d0

13011013333200 has 240 divisors, whose sum is σ = 42071051010560. Its totient is φ = 3436949698560.

The previous prime is 13011013333127. The next prime is 13011013333223. The reversal of 13011013333200 is 233331011031.

It is a tau number, because it is divible by the number of its divisors (240).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 707226402 + ... + 707244798.

Almost surely, 213011013333200 is an apocalyptic number.

13011013333200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011013333200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21035525505280).

13011013333200 is an abundant number, since it is smaller than the sum of its proper divisors (29060037677360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011013333200 is a wasteful number, since it uses less digits than its factorization.

13011013333200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23934 (or 23923 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 13011013333200 its reverse (233331011031), we get a palindrome (13244344344231).

The spelling of 13011013333200 in words is "thirteen trillion, eleven billion, thirteen million, three hundred thirty-three thousand, two hundred".