13011112343 has 2 divisors, whose sum is σ = 13011112344. Its totient is φ = 13011112342.

The previous prime is 13011112267. The next prime is 13011112379. The reversal of 13011112343 is 34321111031.

13011112343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34321111031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13011112343 - 2¹⁴ = 13011095959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13014112343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505556171 + 6505556172.

It is an arithmetic number, because the mean of its divisors is an integer number (6505556172).

Almost surely, 2^13011112343 is an apocalyptic number.

13011112343 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011112343 is an equidigital number, since it uses as much as digits as its factorization.

13011112343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13011112343 its reverse (34321111031), we get a palindrome (47332223374).

The spelling of 13011112343 in words is "thirteen billion, eleven million, one hundred twelve thousand, three hundred forty-three".