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13011130200203 is a prime number
BaseRepresentation
bin1011110101010110001111…
…0010110011000010001011
31201001212000000221021121122
42331111203302303002023
53201133243312401303
643401121455225455
72512010635630562
oct275254362630213
951055000837548
1013011130200203
114166a97886963
12156178921828b
13734c3786b6b5
1432da56308bd9
151786b1893e38
hexbd563cb308b

13011130200203 has 2 divisors, whose sum is σ = 13011130200204. Its totient is φ = 13011130200202.

The previous prime is 13011130200193. The next prime is 13011130200209. The reversal of 13011130200203 is 30200203111031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011130200203 is a prime.

It is a super-2 number, since 2×130111302002032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13011130200209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505565100101 + 6505565100102.

It is an arithmetic number, because the mean of its divisors is an integer number (6505565100102).

Almost surely, 213011130200203 is an apocalyptic number.

13011130200203 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011130200203 is an equidigital number, since it uses as much as digits as its factorization.

13011130200203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13011130200203 its reverse (30200203111031), we get a palindrome (43211333311234).

The spelling of 13011130200203 in words is "thirteen trillion, eleven billion, one hundred thirty million, two hundred thousand, two hundred three".