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130111411211 = 532454932287
BaseRepresentation
bin111100100101100111…
…1101001010000001011
3110102211200120112001222
41321023033221100023
54112432010124321
6135434455032255
712254165514245
oct1711317512013
9412750515058
10130111411211
11501a8555011
122127206b68b
13c366cb2322
1464241cb095
1535b7a1e3ab
hex1e4b3e940b

130111411211 has 4 divisors (see below), whose sum is σ = 132566343552. Its totient is φ = 127656478872.

The previous prime is 130111411201. The next prime is 130111411219. The reversal of 130111411211 is 112114111031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130111411211 - 214 = 130111394827 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130111411211.

It is not an unprimeable number, because it can be changed into a prime (130111411219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1227466091 + ... + 1227466196.

It is an arithmetic number, because the mean of its divisors is an integer number (33141585888).

Almost surely, 2130111411211 is an apocalyptic number.

130111411211 is a deficient number, since it is larger than the sum of its proper divisors (2454932341).

130111411211 is an equidigital number, since it uses as much as digits as its factorization.

130111411211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2454932340.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 130111411211 its reverse (112114111031), we get a palindrome (242225522242).

The spelling of 130111411211 in words is "one hundred thirty billion, one hundred eleven million, four hundred eleven thousand, two hundred eleven".

Divisors: 1 53 2454932287 130111411211