13011144403 has 8 divisors (see below), whose sum is σ = 13114758096. Its totient is φ = 12907596000.

The previous prime is 13011144359. The next prime is 13011144407. The reversal of 13011144403 is 30444111031.

It is a happy number.

13011144403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13011144403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13011144407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 432553 + ... + 461653.

It is an arithmetic number, because the mean of its divisors is an integer number (1639344762).

Almost surely, 2^13011144403 is an apocalyptic number.

13011144403 is a deficient number, since it is larger than the sum of its proper divisors (103613693).

13011144403 is a wasteful number, since it uses less digits than its factorization.

13011144403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32645.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13011144403 its reverse (30444111031), we get a palindrome (43455255434).

The spelling of 13011144403 in words is "thirteen billion, eleven million, one hundred forty-four thousand, four hundred three".