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130112203312997 is a prime number
BaseRepresentation
bin11101100101011000011011…
…101010001100111101100101
3122001200121100011100011100222
4131211120123222030331211
5114023224243022003442
61140420415424214125
736256203456140123
oct3545303352147545
9561617304304328
10130112203312997
113850430382aa74
121271474976a345
13577a6b33a3699
14241b66dc42913
1510097b4d148d2
hex76561ba8cf65

130112203312997 has 2 divisors, whose sum is σ = 130112203312998. Its totient is φ = 130112203312996.

The previous prime is 130112203312981. The next prime is 130112203312999. The reversal of 130112203312997 is 799213302211031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128003292333316 + 2108910979681 = 11313854^2 + 1452209^2 .

It is a cyclic number.

It is not a de Polignac number, because 130112203312997 - 24 = 130112203312981 is a prime.

Together with 130112203312999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130112203312999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056101656498 + 65056101656499.

It is an arithmetic number, because the mean of its divisors is an integer number (65056101656499).

Almost surely, 2130112203312997 is an apocalyptic number.

It is an amenable number.

130112203312997 is a deficient number, since it is larger than the sum of its proper divisors (1).

130112203312997 is an equidigital number, since it uses as much as digits as its factorization.

130112203312997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122472, while the sum is 44.

The spelling of 130112203312997 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred three million, three hundred twelve thousand, nine hundred ninety-seven".