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13011302233 = 13794973009
BaseRepresentation
bin11000001111000100…
…01011011101011001
31020120210001122012201
430013202023131121
5203121343132413
65551033210201
7640301146516
oct140742133531
936523048181
1013011302233
1155775a4a46
122631560961
1312c482b207
148b606c30d
155124359dd
hex30788b759

13011302233 has 4 divisors (see below), whose sum is σ = 13106275380. Its totient is φ = 12916329088.

The previous prime is 13011302221. The next prime is 13011302251. The reversal of 13011302233 is 33220311031.

13011302233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33220311031 = 171954135943.

It can be written as a sum of positive squares in 2 ways, for example, as 5155670809 + 7855631424 = 71803^2 + 88632^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011302233 - 213 = 13011294041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13011302233.

It is not an unprimeable number, because it can be changed into a prime (13011302333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47486368 + ... + 47486641.

It is an arithmetic number, because the mean of its divisors is an integer number (3276568845).

Almost surely, 213011302233 is an apocalyptic number.

It is an amenable number.

13011302233 is a deficient number, since it is larger than the sum of its proper divisors (94973147).

13011302233 is an equidigital number, since it uses as much as digits as its factorization.

13011302233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94973146.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13011302233 its reverse (33220311031), we get a palindrome (46231613264).

The spelling of 13011302233 in words is "thirteen billion, eleven million, three hundred two thousand, two hundred thirty-three".

Divisors: 1 137 94973009 13011302233