13011303102101 has 4 divisors (see below), whose sum is σ = 13042208810604. Its totient is φ = 12980397393600.

The previous prime is 13011303102079. The next prime is 13011303102103. The reversal of 13011303102101 is 10120130311031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 257047986001 + 12754255116100 = 506999^2 + 3571310^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011303102101 - 2¹⁴ = 13011303085717 is a prime.

It is a super-2 number, since 2×13011303102101² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13011303102101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011303102103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15452853620 + ... + 15452854461.

It is an arithmetic number, because the mean of its divisors is an integer number (3260552202651).

Almost surely, 2^{13011303102101} is an apocalyptic number.

It is an amenable number.

13011303102101 is a deficient number, since it is larger than the sum of its proper divisors (30905708503).

13011303102101 is an equidigital number, since it uses as much as digits as its factorization.

13011303102101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30905708502.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13011303102101 its reverse (10120130311031), we get a palindrome (23131433413132).

The spelling of 13011303102101 in words is "thirteen trillion, eleven billion, three hundred three million, one hundred two thousand, one hundred one".