13011312001023 has 12 divisors (see below), whose sum is σ = 21478991239888. Its totient is φ = 7435035429120.

The previous prime is 13011312001021. The next prime is 13011312001069. The reversal of 13011312001023 is 32010021311031.

13011312001023 is a `hidden beast` number, since 1 + 301 + 131 + 200 + 10 + 23 = 666.

It is not a de Polignac number, because 13011312001023 - 2¹ = 13011312001021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011312000987 and 13011312001005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011312001021) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 103264380898 + ... + 103264381023.

Almost surely, 2^{13011312001023} is an apocalyptic number.

13011312001023 is a deficient number, since it is larger than the sum of its proper divisors (8467679238865).

13011312001023 is a wasteful number, since it uses less digits than its factorization.

13011312001023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 206528761934 (or 206528761931 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13011312001023 its reverse (32010021311031), we get a palindrome (45021333312054).

The spelling of 13011312001023 in words is "thirteen trillion, eleven billion, three hundred twelve million, one thousand, twenty-three".