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13011312012 = 2231084276001
BaseRepresentation
bin11000001111000100…
…01101110110001100
31020120210002010121220
430013202031312030
5203121343441022
65551033323340
7640301220156
oct140742156614
936523063556
1013011312012
115577601326
122631566550
1312c48327ba
148b6071ad6
1551243885c
hex30788dd8c

13011312012 has 12 divisors (see below), whose sum is σ = 30359728056. Its totient is φ = 4337104000.

The previous prime is 13011312007. The next prime is 13011312059. The reversal of 13011312012 is 21021311031.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 13011311982 and 13011312000.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542137989 + ... + 542138012.

It is an arithmetic number, because the mean of its divisors is an integer number (2529977338).

Almost surely, 213011312012 is an apocalyptic number.

13011312012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13011312012 is an abundant number, since it is smaller than the sum of its proper divisors (17348416044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011312012 is a wasteful number, since it uses less digits than its factorization.

13011312012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1084276008 (or 1084276006 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13011312012 its reverse (21021311031), we get a palindrome (34032623043).

The spelling of 13011312012 in words is "thirteen billion, eleven million, three hundred twelve thousand, twelve".

Divisors: 1 2 3 4 6 12 1084276001 2168552002 3252828003 4337104004 6505656006 13011312012