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1301132020211 is a prime number
BaseRepresentation
bin10010111011110001100…
…000110000100111110011
311121101110010110001000122
4102323301200300213303
5132304204244121321
62433422022440455
7163001156456012
oct22736140604763
94541403401018
101301132020211
11461897117791
1219020259312b
13959087a979a
1446d91a60a79
1523ca34d38ab
hex12ef18309f3

1301132020211 has 2 divisors, whose sum is σ = 1301132020212. Its totient is φ = 1301132020210.

The previous prime is 1301132020187. The next prime is 1301132020231. The reversal of 1301132020211 is 1120202311031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1301132020211 - 214 = 1301132003827 is a prime.

It is a super-2 number, since 2×13011320202112 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1301132020211.

It is not a weakly prime, because it can be changed into another prime (1301132020231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650566010105 + 650566010106.

It is an arithmetic number, because the mean of its divisors is an integer number (650566010106).

Almost surely, 21301132020211 is an apocalyptic number.

1301132020211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301132020211 is an equidigital number, since it uses as much as digits as its factorization.

1301132020211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1301132020211 its reverse (1120202311031), we get a palindrome (2421334331242).

The spelling of 1301132020211 in words is "one trillion, three hundred one billion, one hundred thirty-two million, twenty thousand, two hundred eleven".