1301133111101 has 2 divisors, whose sum is σ = 1301133111102. Its totient is φ = 1301133111100.

The previous prime is 1301133111077. The next prime is 1301133111107. The reversal of 1301133111101 is 1011113311031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181590740100 + 119542371001 = 1087010^2 + 345749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1301133111101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1301133111101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301133111107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650566555550 + 650566555551.

It is an arithmetic number, because the mean of its divisors is an integer number (650566555551).

Almost surely, 2^{1301133111101} is an apocalyptic number.

It is an amenable number.

1301133111101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301133111101 is an equidigital number, since it uses as much as digits as its factorization.

1301133111101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 1301133111101 its reverse (1011113311031), we get a palindrome (2312246422132).

The spelling of 1301133111101 in words is "one trillion, three hundred one billion, one hundred thirty-three million, one hundred eleven thousand, one hundred one".