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13011412303 is a prime number
BaseRepresentation
bin11000001111000101…
…00110010101001111
31020120210021020012101
430013202212111033
5203121410143203
65551035415531
7640302115441
oct140742462517
936523236171
1013011412303
11557766a70a
1226315b45a7
1312c4869346
148b609a491
1551245841d
hex3078a654f

13011412303 has 2 divisors, whose sum is σ = 13011412304. Its totient is φ = 13011412302.

The previous prime is 13011412291. The next prime is 13011412307. The reversal of 13011412303 is 30321411031.

13011412303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13011412303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011412307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505706151 + 6505706152.

It is an arithmetic number, because the mean of its divisors is an integer number (6505706152).

Almost surely, 213011412303 is an apocalyptic number.

13011412303 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011412303 is an equidigital number, since it uses as much as digits as its factorization.

13011412303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13011412303 its reverse (30321411031), we get a palindrome (43332823334).

The spelling of 13011412303 in words is "thirteen billion, eleven million, four hundred twelve thousand, three hundred three".