Base | Representation |
---|---|
bin | 11101100101011010011001… |
… | …001111010110101001110110 |
3 | 122001200210202222211022111220 |
4 | 131211122121033112221312 |
5 | 114023243101403012042 |
6 | 1140421404450211210 |
7 | 36256306621334424 |
oct | 3545323117265166 |
9 | 561623688738456 |
10 | 130114310204022 |
11 | 38505195045421 |
12 | 12715037283b06 |
13 | 577a95aa34c71 |
14 | 241b7cd9a4114 |
15 | 1009889c8d8ec |
hex | 7656993d6a76 |
130114310204022 has 64 divisors (see below), whose sum is σ = 275338727801856. Its totient is φ = 40906119260160.
The previous prime is 130114310204017. The next prime is 130114310204071. The reversal of 130114310204022 is 220402013411031.
It is a junction number, because it is equal to n+sod(n) for n = 130114310203983 and 130114310204001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34715622 + ... + 38280582.
It is an arithmetic number, because the mean of its divisors is an integer number (4302167621904).
Almost surely, 2130114310204022 is an apocalyptic number.
130114310204022 is an abundant number, since it is smaller than the sum of its proper divisors (145224417597834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130114310204022 is a wasteful number, since it uses less digits than its factorization.
130114310204022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3568685.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 130114310204022 its reverse (220402013411031), we get a palindrome (350516323615053).
The spelling of 130114310204022 in words is "one hundred thirty trillion, one hundred fourteen billion, three hundred ten million, two hundred four thousand, twenty-two".
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