Base | Representation |
---|---|
bin | 10010111011110101110… |
… | …100001001011011110100 |
3 | 11121101122011021201210000 |
4 | 102323311310021123310 |
5 | 132304331234231234 |
6 | 2433433122031300 |
7 | 163003024210044 |
oct | 22736564113364 |
9 | 4541564251700 |
10 | 1301204211444 |
11 | 461923945065 |
12 | 1902227a8530 |
13 | 9591a7347a7 |
14 | 46d9b493724 |
15 | 23ca99e3899 |
hex | 12ef5d096f4 |
1301204211444 has 240 divisors, whose sum is σ = 3534034996800. Its totient is φ = 417188620800.
The previous prime is 1301204211397. The next prime is 1301204211481. The reversal of 1301204211444 is 4441124021031.
1301204211444 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 2 + 0 + 4 + 211 + 444 = 666.
It is a super-3 number, since 3×13012042114443 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 305516587 + ... + 305520845.
It is an arithmetic number, because the mean of its divisors is an integer number (14725145820).
Almost surely, 21301204211444 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1301204211444, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1767017498400).
1301204211444 is an abundant number, since it is smaller than the sum of its proper divisors (2232830785356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301204211444 is a wasteful number, since it uses less digits than its factorization.
1301204211444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4636 (or 4625 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 1301204211444 its reverse (4441124021031), we get a palindrome (5742328232475).
The spelling of 1301204211444 in words is "one trillion, three hundred one billion, two hundred four million, two hundred eleven thousand, four hundred forty-four".
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