Base | Representation |
---|---|
bin | 111100100101111010… |
… | …0101001110110110101 |
3 | 110102212100211102102222 |
4 | 1321023310221312311 |
5 | 4112442001104023 |
6 | 135435443012125 |
7 | 12254344132343 |
oct | 1711364516665 |
9 | 412770742388 |
10 | 130121113013 |
11 | 50202a81131 |
12 | 2127536a045 |
13 | c368ccb238 |
14 | 64255d4993 |
15 | 35b87d8cc8 |
hex | 1e4bd29db5 |
130121113013 has 2 divisors, whose sum is σ = 130121113014. Its totient is φ = 130121113012.
The previous prime is 130121112997. The next prime is 130121113019. The reversal of 130121113013 is 310311121031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129525850609 + 595262404 = 359897^2 + 24398^2 .
It is a cyclic number.
It is not a de Polignac number, because 130121113013 - 24 = 130121112997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130121112982 and 130121113000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130121113019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65060556506 + 65060556507.
It is an arithmetic number, because the mean of its divisors is an integer number (65060556507).
Almost surely, 2130121113013 is an apocalyptic number.
It is an amenable number.
130121113013 is a deficient number, since it is larger than the sum of its proper divisors (1).
130121113013 is an equidigital number, since it uses as much as digits as its factorization.
130121113013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 130121113013 its reverse (310311121031), we get a palindrome (440432234044).
The spelling of 130121113013 in words is "one hundred thirty billion, one hundred twenty-one million, one hundred thirteen thousand, thirteen".
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