Search a number
-
+
13012150400000 = 2105567137443
BaseRepresentation
bin1011110101011010000010…
…0110100011010000000000
31201001221122010121210122022
42331112200212203100000
53201142341000300000
643401411021501012
72512045134322163
oct275264046432000
951057563553568
1013012150400000
114167470747094
121561a12a11768
1373506b02bc0b
1432db119d3ada
15178721215585
hexbd5a09a3400

13012150400000 has 528 divisors, whose sum is σ = 33313560420672. Its totient is φ = 5078261760000.

The previous prime is 13012150399979. The next prime is 13012150400063. The reversal of 13012150400000 is 405121031.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 29372799779 + ... + 29372800221.

Almost surely, 213012150400000 is an apocalyptic number.

13012150400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13012150400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16656780210336).

13012150400000 is an abundant number, since it is smaller than the sum of its proper divisors (20301410020672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13012150400000 is an frugal number, since it uses more digits than its factorization.

13012150400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 692 (or 654 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 13012150400000 its reverse (405121031), we get a palindrome (13012555521031).

The spelling of 13012150400000 in words is "thirteen trillion, twelve billion, one hundred fifty million, four hundred thousand".