Base | Representation |
---|---|
bin | 1011110101011010101010… |
… | …1110010011010011110100 |
3 | 1201001222001222010201222002 |
4 | 2331112222232103103310 |
5 | 3201143212433012040 |
6 | 43401435525154432 |
7 | 2512052265533504 |
oct | 275265256232364 |
9 | 51058058121862 |
10 | 13012320204020 |
11 | 4167548585395 |
12 | 1561a5b85ba18 |
13 | 735097272c77 |
14 | 32db2a395a04 |
15 | 1787310a7a15 |
hex | bd5aab934f4 |
13012320204020 has 12 divisors (see below), whose sum is σ = 27325872428484. Its totient is φ = 5204928081600.
The previous prime is 13012320203983. The next prime is 13012320204113. The reversal of 13012320204020 is 2040202321031.
It can be written as a sum of positive squares in 2 ways, for example, as 4579719840784 + 8432600363236 = 2140028^2 + 2903894^2 .
It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 650616010201 = 13012320204020 / (1 + 3 + 0 + 1 + 2 + 3 + 2 + 0 + 2 + 0 + 4 + 0 + 2 + 0).
It is a junction number, because it is equal to n+sod(n) for n = 13012320203983 and 13012320204001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325308005081 + ... + 325308005120.
It is an arithmetic number, because the mean of its divisors is an integer number (2277156035707).
Almost surely, 213012320204020 is an apocalyptic number.
13012320204020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13012320204020 is an abundant number, since it is smaller than the sum of its proper divisors (14313552224464).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13012320204020 is a wasteful number, since it uses less digits than its factorization.
13012320204020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 650616010210 (or 650616010208 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 13012320204020 its reverse (2040202321031), we get a palindrome (15052522525051).
The spelling of 13012320204020 in words is "thirteen trillion, twelve billion, three hundred twenty million, two hundred four thousand, twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •