Base | Representation |
---|---|
bin | 100110110001111… |
… | …0101100011001011 |
3 | 10100200111211201111 |
4 | 1031203311203023 |
5 | 10131104140021 |
6 | 333042031151 |
7 | 44150233441 |
oct | 11543654313 |
9 | 3320454644 |
10 | 1301240011 |
11 | 608574975 |
12 | 3039484b7 |
13 | 179780506 |
14 | c4b64b91 |
15 | 793878e1 |
hex | 4d8f58cb |
1301240011 has 4 divisors (see below), whose sum is σ = 1307075392. Its totient is φ = 1295404632.
The previous prime is 1301240009. The next prime is 1301240077. The reversal of 1301240011 is 1100421031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1301240011 - 21 = 1301240009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1301239973 and 1301240000.
It is not an unprimeable number, because it can be changed into a prime (1301210011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2917356 + ... + 2917801.
It is an arithmetic number, because the mean of its divisors is an integer number (326768848).
Almost surely, 21301240011 is an apocalyptic number.
1301240011 is a deficient number, since it is larger than the sum of its proper divisors (5835381).
1301240011 is an equidigital number, since it uses as much as digits as its factorization.
1301240011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5835380.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1301240011 is about 36072.7045146327. The cubic root of 1301240011 is about 1091.7397828334.
Adding to 1301240011 its reverse (1100421031), we get a palindrome (2401661042).
The spelling of 1301240011 in words is "one billion, three hundred one million, two hundred forty thousand, eleven".
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