Search a number
-
+
130124048334331 is a prime number
BaseRepresentation
bin11101100101100011011101…
…101011010111110111111011
3122001201201220122211120221211
4131211203131223113313323
5114023423022333144311
61140430055040143551
736260103136150042
oct3545433553276773
9561651818746854
10130124048334331
1138509331a598a7
1212716ab4607bb7
13577b8503b514c
14241c07503b559
151009c59b70821
hex7658ddad7dfb

130124048334331 has 2 divisors, whose sum is σ = 130124048334332. Its totient is φ = 130124048334330.

The previous prime is 130124048334233. The next prime is 130124048334349. The reversal of 130124048334331 is 133433840421031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130124048334331 - 211 = 130124048332283 is a prime.

It is a super-2 number, since 2×1301240483343312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130124048334361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65062024167165 + 65062024167166.

It is an arithmetic number, because the mean of its divisors is an integer number (65062024167166).

Almost surely, 2130124048334331 is an apocalyptic number.

130124048334331 is a deficient number, since it is larger than the sum of its proper divisors (1).

130124048334331 is an equidigital number, since it uses as much as digits as its factorization.

130124048334331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 40.

Adding to 130124048334331 its reverse (133433840421031), we get a palindrome (263557888755362).

The spelling of 130124048334331 in words is "one hundred thirty trillion, one hundred twenty-four billion, forty-eight million, three hundred thirty-four thousand, three hundred thirty-one".