Base | Representation |
---|---|
bin | 11101100101100011011101… |
… | …101011010111111000001101 |
3 | 122001201201220122211120222111 |
4 | 131211203131223113320031 |
5 | 114023423022333144344 |
6 | 1140430055040144021 |
7 | 36260103136150066 |
oct | 3545433553277015 |
9 | 561651818746874 |
10 | 130124048334349 |
11 | 38509331a59913 |
12 | 12716ab4608011 |
13 | 577b8503b5164 |
14 | 241c07503b56d |
15 | 1009c59b70834 |
hex | 7658ddad7e0d |
130124048334349 has 2 divisors, whose sum is σ = 130124048334350. Its totient is φ = 130124048334348.
The previous prime is 130124048334331. The next prime is 130124048334353. The reversal of 130124048334349 is 943433840421031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128156957933449 + 1967090400900 = 11320643^2 + 1402530^2 .
It is a cyclic number.
It is not a de Polignac number, because 130124048334349 - 29 = 130124048333837 is a prime.
It is a super-2 number, since 2×1301240483343492 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130124048344349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65062024167174 + 65062024167175.
It is an arithmetic number, because the mean of its divisors is an integer number (65062024167175).
Almost surely, 2130124048334349 is an apocalyptic number.
It is an amenable number.
130124048334349 is a deficient number, since it is larger than the sum of its proper divisors (1).
130124048334349 is an equidigital number, since it uses as much as digits as its factorization.
130124048334349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2985984, while the sum is 49.
The spelling of 130124048334349 in words is "one hundred thirty trillion, one hundred twenty-four billion, forty-eight million, three hundred thirty-four thousand, three hundred forty-nine".
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