13012420111 has 2 divisors, whose sum is σ = 13012420112. Its totient is φ = 13012420110.

The previous prime is 13012420079. The next prime is 13012420129. The reversal of 13012420111 is 11102421031.

13012420111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13012420111 - 2⁵ = 13012420079 is a prime.

It is a zygodrome in base 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13012420181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506210055 + 6506210056.

It is an arithmetic number, because the mean of its divisors is an integer number (6506210056).

Almost surely, 2^13012420111 is an apocalyptic number.

13012420111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012420111 is an equidigital number, since it uses as much as digits as its factorization.

13012420111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13012420111 its reverse (11102421031), we get a palindrome (24114841142).

The spelling of 13012420111 in words is "thirteen billion, twelve million, four hundred twenty thousand, one hundred eleven".