13013000333 has 4 divisors (see below), whose sum is σ = 13014972960. Its totient is φ = 13011027708.

The previous prime is 13013000311. The next prime is 13013000339. The reversal of 13013000333 is 33300031031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13013000333 - 2¹⁶ = 13012934797 is a prime.

It is a super-2 number, since 2×13013000333² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13013000339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 976385 + ... + 989622.

It is an arithmetic number, because the mean of its divisors is an integer number (3253743240).

Almost surely, 2^13013000333 is an apocalyptic number.

It is an amenable number.

13013000333 is a deficient number, since it is larger than the sum of its proper divisors (1972627).

13013000333 is an equidigital number, since it uses as much as digits as its factorization.

13013000333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1972626.

The product of its (nonzero) digits is 243, while the sum is 17.

Adding to 13013000333 its reverse (33300031031), we get a palindrome (46313031364).

The spelling of 13013000333 in words is "thirteen billion, thirteen million, three hundred thirty-three", and thus it is an aban number.