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13013024321 = 111183002211
BaseRepresentation
bin11000001111010001…
…01111111001000001
31020120220022010110202
430013220233321001
5203122313234241
65551134134545
7640321611263
oct140750577101
936526263422
1013013024321
115578570860
122632051455
1312c4cb1cbb
148b6399b33
15512675d9b
hex307a2fe41

13013024321 has 4 divisors (see below), whose sum is σ = 14196026544. Its totient is φ = 11830022100.

The previous prime is 13013024303. The next prime is 13013024347. The reversal of 13013024321 is 12342031031.

13013024321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13013024321 - 26 = 13013024257 is a prime.

It is a super-2 number, since 2×130130243212 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13013024293 and 13013024302.

It is not an unprimeable number, because it can be changed into a prime (13013026321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591501095 + ... + 591501116.

It is an arithmetic number, because the mean of its divisors is an integer number (3549006636).

Almost surely, 213013024321 is an apocalyptic number.

13013024321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13013024321 is a deficient number, since it is larger than the sum of its proper divisors (1183002223).

13013024321 is a wasteful number, since it uses less digits than its factorization.

13013024321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1183002222.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13013024321 its reverse (12342031031), we get a palindrome (25355055352).

It can be divided in two parts, 130130 and 24321, that added together give a palindrome (154451).

The spelling of 13013024321 in words is "thirteen billion, thirteen million, twenty-four thousand, three hundred twenty-one".

Divisors: 1 11 1183002211 13013024321