Base | Representation |
---|---|
bin | 111100100110001100… |
… | …0001111010001111101 |
3 | 110102220000101100111121 |
4 | 1321030120033101331 |
5 | 4113001343110331 |
6 | 135440414550541 |
7 | 12254516333545 |
oct | 1711430172175 |
9 | 412800340447 |
10 | 130130441341 |
11 | 5020827269a |
12 | 21278508451 |
13 | c36ac16164 |
14 | 6426942325 |
15 | 35b952cc11 |
hex | 1e4c60f47d |
130130441341 has 2 divisors, whose sum is σ = 130130441342. Its totient is φ = 130130441340.
The previous prime is 130130441321. The next prime is 130130441351. The reversal of 130130441341 is 143144031031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80753157241 + 49377284100 = 284171^2 + 222210^2 .
It is an emirp because it is prime and its reverse (143144031031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130130441341 - 29 = 130130440829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130130441321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065220670 + 65065220671.
It is an arithmetic number, because the mean of its divisors is an integer number (65065220671).
Almost surely, 2130130441341 is an apocalyptic number.
It is an amenable number.
130130441341 is a deficient number, since it is larger than the sum of its proper divisors (1).
130130441341 is an equidigital number, since it uses as much as digits as its factorization.
130130441341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 130130441341 its reverse (143144031031), we get a palindrome (273274472372).
The spelling of 130130441341 in words is "one hundred thirty billion, one hundred thirty million, four hundred forty-one thousand, three hundred forty-one".
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