Base | Representation |
---|---|
bin | 11101100101101010000010… |
… | …001111100011100101111011 |
3 | 122001202102010101210020221111 |
4 | 131211222002033203211323 |
5 | 114024032000142001420 |
6 | 1140433223133021151 |
7 | 36260443034353324 |
oct | 3545520217434573 |
9 | 561672111706844 |
10 | 130131104250235 |
11 | 38511322924960 |
12 | 127183436247b7 |
13 | 577c40616810a |
14 | 241c54419144b |
15 | 100a01e33245a |
hex | 765a823e397b |
130131104250235 has 8 divisors (see below), whose sum is σ = 170353445564016. Its totient is φ = 94640803091040.
The previous prime is 130131104250209. The next prime is 130131104250269. The reversal of 130131104250235 is 532052401131031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130131104250235 - 27 = 130131104250107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130131104250197 and 130131104250206.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1183010038584 + ... + 1183010038693.
It is an arithmetic number, because the mean of its divisors is an integer number (21294180695502).
Almost surely, 2130131104250235 is an apocalyptic number.
130131104250235 is a deficient number, since it is larger than the sum of its proper divisors (40222341313781).
130131104250235 is a wasteful number, since it uses less digits than its factorization.
130131104250235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2366020077293.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 130131104250235 its reverse (532052401131031), we get a palindrome (662183505381266).
The spelling of 130131104250235 in words is "one hundred thirty trillion, one hundred thirty-one billion, one hundred four million, two hundred fifty thousand, two hundred thirty-five".
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