Base | Representation |
---|---|
bin | 11101100101101010001000… |
… | …101000011011010010001100 |
3 | 122001202102101212110201012020 |
4 | 131211222020220123102030 |
5 | 114024032210111324400 |
6 | 1140433241522210140 |
7 | 36260445505402653 |
oct | 3545521050332214 |
9 | 561672355421166 |
10 | 130131211433100 |
11 | 38511378381a39 |
12 | 127183734b3950 |
13 | 577c422425127 |
14 | 241c5544d219a |
15 | 100a0289552a0 |
hex | 765a88a1b48c |
130131211433100 has 144 divisors (see below), whose sum is σ = 381927106246560. Its totient is φ = 34203296563200.
The previous prime is 130131211433033. The next prime is 130131211433183. The reversal of 130131211433100 is 1334112131031.
130131211433100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1301312114331002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 30613780 + ... + 34604420.
Almost surely, 2130131211433100 is an apocalyptic number.
130131211433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130131211433100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (190963553123280).
130131211433100 is an abundant number, since it is smaller than the sum of its proper divisors (251795894813460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130131211433100 is a wasteful number, since it uses less digits than its factorization.
130131211433100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3992220 (or 3992213 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 130131211433100 its reverse (1334112131031), we get a palindrome (131465323564131).
The spelling of 130131211433100 in words is "one hundred thirty trillion, one hundred thirty-one billion, two hundred eleven million, four hundred thirty-three thousand, one hundred".
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