Base | Representation |
---|---|
bin | 11000001111010010… |
… | …01100111111010111 |
3 | 1020120220112011222012 |
4 | 30013221030333113 |
5 | 203122331043021 |
6 | 5551140454435 |
7 | 640322615624 |
oct | 140751147727 |
9 | 36526464865 |
10 | 13013143511 |
11 | 5578642365 |
12 | 26320aa41b |
13 | 12c5024324 |
14 | 8b63cb34b |
15 | 51269b35b |
hex | 307a4cfd7 |
13013143511 has 2 divisors, whose sum is σ = 13013143512. Its totient is φ = 13013143510.
The previous prime is 13013143483. The next prime is 13013143579. The reversal of 13013143511 is 11534131031.
It is a weak prime.
It is an emirp because it is prime and its reverse (11534131031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13013143511 - 230 = 11939401687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013145511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506571755 + 6506571756.
It is an arithmetic number, because the mean of its divisors is an integer number (6506571756).
Almost surely, 213013143511 is an apocalyptic number.
13013143511 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013143511 is an equidigital number, since it uses as much as digits as its factorization.
13013143511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 13013143511 its reverse (11534131031), we get a palindrome (24547274542).
The spelling of 13013143511 in words is "thirteen billion, thirteen million, one hundred forty-three thousand, five hundred eleven".
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