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13013200049 is a prime number
BaseRepresentation
bin11000001111010010…
…11010110010110001
31020120220122001112012
430013221122302301
5203122334400144
65551142012305
7640323242513
oct140751326261
936526561465
1013013200049
115578680893
122632117095
1312c5043c95
148b6403bb3
155126ace9e
hex307a5acb1

13013200049 has 2 divisors, whose sum is σ = 13013200050. Its totient is φ = 13013200048.

The previous prime is 13013200027. The next prime is 13013200063. The reversal of 13013200049 is 94000231031.

13013200049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12903369649 + 109830400 = 113593^2 + 10480^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013200049 - 212 = 13013195953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13013199997 and 13013200033.

It is not a weakly prime, because it can be changed into another prime (13013200009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506600024 + 6506600025.

It is an arithmetic number, because the mean of its divisors is an integer number (6506600025).

Almost surely, 213013200049 is an apocalyptic number.

It is an amenable number.

13013200049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013200049 is an equidigital number, since it uses as much as digits as its factorization.

13013200049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

The spelling of 13013200049 in words is "thirteen billion, thirteen million, two hundred thousand, forty-nine".