130132113100333 has 4 divisors (see below), whose sum is σ = 130177982723580. Its totient is φ = 130086243477088.

The previous prime is 130132113100291. The next prime is 130132113100343. The reversal of 130132113100333 is 333001311231031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 65599842993129 + 64532270107204 = 8099373^2 + 8033198^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130132113100333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130132113100298 and 130132113100307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130132113100343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22934807368 + ... + 22934813041.

It is an arithmetic number, because the mean of its divisors is an integer number (32544495680895).

Almost surely, 2^{130132113100333} is an apocalyptic number.

It is an amenable number.

130132113100333 is a deficient number, since it is larger than the sum of its proper divisors (45869623247).

130132113100333 is an equidigital number, since it uses as much as digits as its factorization.

130132113100333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45869623246.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 130132113100333 its reverse (333001311231031), we get a palindrome (463133424331364).

The spelling of 130132113100333 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred thousand, three hundred thirty-three".