Base | Representation |
---|---|
bin | 11101100101101010111110… |
… | …011000000000111000110111 |
3 | 122001202111201201010011010022 |
4 | 131211222332120000320313 |
5 | 114024041031423202333 |
6 | 1140433511212115355 |
7 | 36260510034424304 |
oct | 3545527630007067 |
9 | 561674651104108 |
10 | 130132113100343 |
11 | 385117a0342982 |
12 | 12718585465b5b |
13 | 577c537183643 |
14 | 241c5dc1640ab |
15 | 100a07cbb0c98 |
hex | 765abe600e37 |
130132113100343 has 2 divisors, whose sum is σ = 130132113100344. Its totient is φ = 130132113100342.
The previous prime is 130132113100291. The next prime is 130132113100361. The reversal of 130132113100343 is 343001311231031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130132113100343 - 218 = 130132112838199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130132113100373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066056550171 + 65066056550172.
It is an arithmetic number, because the mean of its divisors is an integer number (65066056550172).
Almost surely, 2130132113100343 is an apocalyptic number.
130132113100343 is a deficient number, since it is larger than the sum of its proper divisors (1).
130132113100343 is an equidigital number, since it uses as much as digits as its factorization.
130132113100343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 130132113100343 its reverse (343001311231031), we get a palindrome (473133424331374).
The spelling of 130132113100343 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred thousand, three hundred forty-three".
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