Base | Representation |
---|---|
bin | 11101100101101010111110… |
… | …011000000000111000110110 |
3 | 122001202111201201010011010021 |
4 | 131211222332120000320312 |
5 | 114024041031423202332 |
6 | 1140433511212115354 |
7 | 36260510034424303 |
oct | 3545527630007066 |
9 | 561674651104107 |
10 | 130132113100342 |
11 | 385117a0342981 |
12 | 12718585465b5a |
13 | 577c537183642 |
14 | 241c5dc1640aa |
15 | 100a07cbb0c97 |
hex | 765abe600e36 |
130132113100342 has 4 divisors (see below), whose sum is σ = 195198169650516. Its totient is φ = 65066056550170.
The previous prime is 130132113100291. The next prime is 130132113100343. The reversal of 130132113100342 is 243001311231031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130132113100343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32533028275084 + ... + 32533028275087.
It is an arithmetic number, because the mean of its divisors is an integer number (48799542412629).
Almost surely, 2130132113100342 is an apocalyptic number.
130132113100342 is a deficient number, since it is larger than the sum of its proper divisors (65066056550174).
130132113100342 is an equidigital number, since it uses as much as digits as its factorization.
130132113100342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65066056550173.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130132113100342 its reverse (243001311231031), we get a palindrome (373133424331373).
The spelling of 130132113100342 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred thousand, three hundred forty-two".
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