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130132121113 is a prime number
BaseRepresentation
bin111100100110001111…
…0101001011000011001
3110102220010112200201101
41321030132221120121
54113002310333423
6135440514551401
712254536531051
oct1711436513031
9412803480641
10130132121113
115020920a735
1221278b98561
13c36b3838c7
146426c5c561
1535b97607ad
hex1e4c7a9619

130132121113 has 2 divisors, whose sum is σ = 130132121114. Its totient is φ = 130132121112.

The previous prime is 130132121111. The next prime is 130132121131. The reversal of 130132121113 is 311121231031.

Together with next prime (130132121131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67718091529 + 62414029584 = 260227^2 + 249828^2 .

It is a cyclic number.

It is not a de Polignac number, because 130132121113 - 21 = 130132121111 is a prime.

Together with 130132121111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (130132121111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066060556 + 65066060557.

It is an arithmetic number, because the mean of its divisors is an integer number (65066060557).

Almost surely, 2130132121113 is an apocalyptic number.

It is an amenable number.

130132121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130132121113 is an equidigital number, since it uses as much as digits as its factorization.

130132121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 130132121113 its reverse (311121231031), we get a palindrome (441253352144).

The spelling of 130132121113 in words is "one hundred thirty billion, one hundred thirty-two million, one hundred twenty-one thousand, one hundred thirteen".