130132121131 has 2 divisors, whose sum is σ = 130132121132. Its totient is φ = 130132121130.

The previous prime is 130132121113. The next prime is 130132121149. The reversal of 130132121131 is 131121231031.

Together with previous prime (130132121113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (130132121113) and next prime (130132121149).

It is a cyclic number.

It is not a de Polignac number, because 130132121131 - 2⁵ = 130132121099 is a prime.

It is a super-2 number, since 2×130132121131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130132121099 and 130132121108.

It is not a weakly prime, because it can be changed into another prime (130132121111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066060565 + 65066060566.

It is an arithmetic number, because the mean of its divisors is an integer number (65066060566).

Almost surely, 2^130132121131 is an apocalyptic number.

130132121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130132121131 is an equidigital number, since it uses as much as digits as its factorization.

130132121131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 130132121131 its reverse (131121231031), we get a palindrome (261253352162).

The spelling of 130132121131 in words is "one hundred thirty billion, one hundred thirty-two million, one hundred twenty-one thousand, one hundred thirty-one".