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130132122389 is a prime number
BaseRepresentation
bin111100100110001111…
…0101001101100010101
3110102220010112202110122
41321030132221230111
54113002310404024
6135440515001325
712254536534553
oct1711436515425
9412803482418
10130132122389
1150209210695
1221278b99245
13c36b384369
146426c5cbd3
1535b9760d5e
hex1e4c7a9b15

130132122389 has 2 divisors, whose sum is σ = 130132122390. Its totient is φ = 130132122388.

The previous prime is 130132122299. The next prime is 130132122391. The reversal of 130132122389 is 983221231031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117823995025 + 12308127364 = 343255^2 + 110942^2 .

It is a cyclic number.

It is not a de Polignac number, because 130132122389 - 228 = 129863686933 is a prime.

Together with 130132122391, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130132112389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65066061194 + 65066061195.

It is an arithmetic number, because the mean of its divisors is an integer number (65066061195).

Almost surely, 2130132122389 is an apocalyptic number.

It is an amenable number.

130132122389 is a deficient number, since it is larger than the sum of its proper divisors (1).

130132122389 is an equidigital number, since it uses as much as digits as its factorization.

130132122389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 130132122389 in words is "one hundred thirty billion, one hundred thirty-two million, one hundred twenty-two thousand, three hundred eighty-nine".