Base | Representation |
---|---|
bin | 11101100101101011000000… |
… | …001101111000110000110111 |
3 | 122001202111210212021000120002 |
4 | 131211223000031320300313 |
5 | 114024041112331000210 |
6 | 1140433514234301515 |
7 | 36260510561161031 |
oct | 3545530015706067 |
9 | 561674725230502 |
10 | 130132144000055 |
11 | 3851180682832a |
12 | 1271859388789b |
13 | 577c5406b1cb2 |
14 | 241c6022c8c51 |
15 | 100a0807664a5 |
hex | 765ac0378c37 |
130132144000055 has 4 divisors (see below), whose sum is σ = 156158572800072. Its totient is φ = 104105715200040.
The previous prime is 130132144000049. The next prime is 130132144000093. The reversal of 130132144000055 is 550000441231031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130132144000055 - 24 = 130132144000039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130132143999991 and 130132144000027.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13013214400001 + ... + 13013214400010.
It is an arithmetic number, because the mean of its divisors is an integer number (39039643200018).
Almost surely, 2130132144000055 is an apocalyptic number.
130132144000055 is a deficient number, since it is larger than the sum of its proper divisors (26026428800017).
130132144000055 is an equidigital number, since it uses as much as digits as its factorization.
130132144000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26026428800016.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 130132144000055 its reverse (550000441231031), we get a palindrome (680132585231086).
The spelling of 130132144000055 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred forty-four million, fifty-five", and thus it is an aban number.
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