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130132144000055 = 526026428800011
BaseRepresentation
bin11101100101101011000000…
…001101111000110000110111
3122001202111210212021000120002
4131211223000031320300313
5114024041112331000210
61140433514234301515
736260510561161031
oct3545530015706067
9561674725230502
10130132144000055
113851180682832a
121271859388789b
13577c5406b1cb2
14241c6022c8c51
15100a0807664a5
hex765ac0378c37

130132144000055 has 4 divisors (see below), whose sum is σ = 156158572800072. Its totient is φ = 104105715200040.

The previous prime is 130132144000049. The next prime is 130132144000093. The reversal of 130132144000055 is 550000441231031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 130132144000055 - 24 = 130132144000039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130132143999991 and 130132144000027.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13013214400001 + ... + 13013214400010.

It is an arithmetic number, because the mean of its divisors is an integer number (39039643200018).

Almost surely, 2130132144000055 is an apocalyptic number.

130132144000055 is a deficient number, since it is larger than the sum of its proper divisors (26026428800017).

130132144000055 is an equidigital number, since it uses as much as digits as its factorization.

130132144000055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26026428800016.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 130132144000055 its reverse (550000441231031), we get a palindrome (680132585231086).

The spelling of 130132144000055 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred forty-four million, fifty-five", and thus it is an aban number.

Divisors: 1 5 26026428800011 130132144000055