Base | Representation |
---|---|
bin | 1011110101011110000001… |
… | …1111010001010011010111 |
3 | 1201002001101211110120112001 |
4 | 2331113200133101103113 |
5 | 3201202034342431203 |
6 | 43402105230540131 |
7 | 2512113530623465 |
oct | 275274037212327 |
9 | 51061354416461 |
10 | 13013222233303 |
11 | 4167970773336 |
12 | 1562071967647 |
13 | 7351ac0ca1c6 |
14 | 32dbb40bd835 |
15 | 17878538591d |
hex | bd5e07d14d7 |
13013222233303 has 2 divisors, whose sum is σ = 13013222233304. Its totient is φ = 13013222233302.
The previous prime is 13013222233301. The next prime is 13013222233313. The reversal of 13013222233303 is 30333222231031.
It is a weak prime.
It is an emirp because it is prime and its reverse (30333222231031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13013222233303 - 21 = 13013222233301 is a prime.
Together with 13013222233301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13013222233301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506611116651 + 6506611116652.
It is an arithmetic number, because the mean of its divisors is an integer number (6506611116652).
Almost surely, 213013222233303 is an apocalyptic number.
13013222233303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013222233303 is an equidigital number, since it uses as much as digits as its factorization.
13013222233303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 13013222233303 its reverse (30333222231031), we get a palindrome (43346444464334).
The spelling of 13013222233303 in words is "thirteen trillion, thirteen billion, two hundred twenty-two million, two hundred thirty-three thousand, three hundred three".
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