Base | Representation |
---|---|
bin | 10010111011111101010… |
… | …100011011001010110000 |
3 | 11121101221221012012112000 |
4 | 102323331110123022300 |
5 | 132310111002110300 |
6 | 2433453420334000 |
7 | 163006113311415 |
oct | 22737524331260 |
9 | 4541857165460 |
10 | 1301330113200 |
11 | 461988a179a7 |
12 | 1902589a4300 |
13 | 9593a846a80 |
14 | 46db00a810c |
15 | 23cb5ab2c00 |
hex | 12efd51b2b0 |
1301330113200 has 480 divisors, whose sum is σ = 5004268039680. Its totient is φ = 319286707200.
The previous prime is 1301330113199. The next prime is 1301330113231. The reversal of 1301330113200 is 23110331031.
It is a happy number.
1301330113200 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 330 + 11 + 320 + 0 = 666.
It is a super-2 number, since 2×13013301132002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 43649499 + ... + 43679301.
It is an arithmetic number, because the mean of its divisors is an integer number (10425558416).
Almost surely, 21301330113200 is an apocalyptic number.
1301330113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1301330113200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2502134019840).
1301330113200 is an abundant number, since it is smaller than the sum of its proper divisors (3702937926480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301330113200 is a wasteful number, since it uses less digits than its factorization.
1301330113200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30154 (or 30137 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 1301330113200 its reverse (23110331031), we get a palindrome (1324440444231).
The spelling of 1301330113200 in words is "one trillion, three hundred one billion, three hundred thirty million, one hundred thirteen thousand, two hundred".
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