130133034011333 has 4 divisors (see below), whose sum is σ = 130370937181920. Its totient is φ = 129895130840748.

The previous prime is 130133034011329. The next prime is 130133034011347. The reversal of 130133034011333 is 333110430331031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130133034011333 - 2² = 130133034011329 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130133034011296 and 130133034011305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130133034011363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118951584473 + ... + 118951585566.

It is an arithmetic number, because the mean of its divisors is an integer number (32592734295480).

Almost surely, 2^{130133034011333} is an apocalyptic number.

It is an amenable number.

130133034011333 is a deficient number, since it is larger than the sum of its proper divisors (237903170587).

130133034011333 is an equidigital number, since it uses as much as digits as its factorization.

130133034011333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237903170586.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 130133034011333 its reverse (333110430331031), we get a palindrome (463243464342364).

The spelling of 130133034011333 in words is "one hundred thirty trillion, one hundred thirty-three billion, thirty-four million, eleven thousand, three hundred thirty-three".