Base | Representation |
---|---|
bin | 1011110101011110011100… |
… | …0101110100000000100110 |
3 | 1201002001200112220010011211 |
4 | 2331113213011310000212 |
5 | 3201202301222001410 |
6 | 43402124225022034 |
7 | 2512116344261233 |
oct | 275274705640046 |
9 | 51061615803154 |
10 | 13013333000230 |
11 | 4167a18249152 |
12 | 15620a2a8491a |
13 | 7351c9040674 |
14 | 32dbc4ab478a |
15 | 17878ee6568a |
hex | bd5e7174026 |
13013333000230 has 64 divisors (see below), whose sum is σ = 25132079044800. Its totient is φ = 4836394967040.
The previous prime is 13013333000153. The next prime is 13013333000237. The reversal of 13013333000230 is 3200033331031.
13013333000230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13013333000237) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25130166 + ... + 25642774.
It is an arithmetic number, because the mean of its divisors is an integer number (392688735075).
Almost surely, 213013333000230 is an apocalyptic number.
13013333000230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13013333000230 is a deficient number, since it is larger than the sum of its proper divisors (12118746044570).
13013333000230 is a wasteful number, since it uses less digits than its factorization.
13013333000230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515209.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 13013333000230 its reverse (3200033331031), we get a palindrome (16213366331261).
The spelling of 13013333000230 in words is "thirteen trillion, thirteen billion, three hundred thirty-three million, two hundred thirty", and thus it is an aban number.
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