1301350041301 has 4 divisors (see below), whose sum is σ = 1301612045472. Its totient is φ = 1301088037132.

The previous prime is 1301350041287. The next prime is 1301350041347. The reversal of 1301350041301 is 1031400531031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301350041301 - 2¹⁷ = 1301349910229 is a prime.

It is a super-2 number, since 2×1301350041301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301350042301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130994635 + ... + 131004568.

It is an arithmetic number, because the mean of its divisors is an integer number (325403011368).

Almost surely, 2^{1301350041301} is an apocalyptic number.

It is an amenable number.

1301350041301 is a deficient number, since it is larger than the sum of its proper divisors (262004171).

1301350041301 is an equidigital number, since it uses as much as digits as its factorization.

1301350041301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262004170.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 1301350041301 its reverse (1031400531031), we get a palindrome (2332750572332).

The spelling of 1301350041301 in words is "one trillion, three hundred one billion, three hundred fifty million, forty-one thousand, three hundred one".