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130135315311 = 35535536277
BaseRepresentation
bin111100100110010101…
…0110101001101101111
3110102220100112222100000
41321030222311031233
54113004120042221
6135441111235343
712254605633431
oct1711452651557
9412810488300
10130135315311
115020aaa1571
122127a078b53
13c36bc31771
146427450651
1535b9b91e26
hex1e4cab536f

130135315311 has 12 divisors (see below), whose sum is σ = 194935205192. Its totient is φ = 86756876712.

The previous prime is 130135315291. The next prime is 130135315351. The reversal of 130135315311 is 113513531031.

It is a happy number.

130135315311 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 35 + 315 + 311 = 666.

It is not a de Polignac number, because 130135315311 - 213 = 130135307119 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130135315351) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 267767896 + ... + 267768381.

Almost surely, 2130135315311 is an apocalyptic number.

130135315311 is a deficient number, since it is larger than the sum of its proper divisors (64799889881).

130135315311 is an frugal number, since it uses more digits than its factorization.

130135315311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 535536292 (or 535536280 counting only the distinct ones).

The product of its (nonzero) digits is 2025, while the sum is 27.

Adding to 130135315311 its reverse (113513531031), we get a palindrome (243648846342).

The spelling of 130135315311 in words is "one hundred thirty billion, one hundred thirty-five million, three hundred fifteen thousand, three hundred eleven".

Divisors: 1 3 9 27 81 243 535536277 1606608831 4819826493 14459479479 43378438437 130135315311