Base | Representation |
---|---|
bin | 1011110101100001000000… |
… | …0100100000000111100111 |
3 | 1201002010110110120212101112 |
4 | 2331120100010200013213 |
5 | 3201210203223204341 |
6 | 43402320345015235 |
7 | 2512142363153243 |
oct | 275302004400747 |
9 | 51063413525345 |
10 | 13014020522471 |
11 | 4168240345851 |
12 | 156225518451b |
13 | 7352a8601467 |
14 | 32dc4c121423 |
15 | 1787d04c0aeb |
hex | bd6101201e7 |
13014020522471 has 2 divisors, whose sum is σ = 13014020522472. Its totient is φ = 13014020522470.
The previous prime is 13014020522281. The next prime is 13014020522549. The reversal of 13014020522471 is 17422502041031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13014020522471 - 226 = 13013953413607 is a prime.
It is a super-3 number, since 3×130140205224713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13014020524471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507010261235 + 6507010261236.
It is an arithmetic number, because the mean of its divisors is an integer number (6507010261236).
Almost surely, 213014020522471 is an apocalyptic number.
13014020522471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13014020522471 is an equidigital number, since it uses as much as digits as its factorization.
13014020522471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
The spelling of 13014020522471 in words is "thirteen trillion, fourteen billion, twenty million, five hundred twenty-two thousand, four hundred seventy-one".
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