1301412141031 has 4 divisors (see below), whose sum is σ = 1306360476432. Its totient is φ = 1296463805632.

The previous prime is 1301412140989. The next prime is 1301412141049.

1301412141031 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301412141031 - 2¹⁵ = 1301412108263 is a prime.

It is a super-2 number, since 2×1301412141031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301412140993 and 1301412141011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301412141091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2474167306 + ... + 2474167831.

It is an arithmetic number, because the mean of its divisors is an integer number (326590119108).

Almost surely, 2^{1301412141031} is an apocalyptic number.

1301412141031 is a deficient number, since it is larger than the sum of its proper divisors (4948335401).

1301412141031 is an equidigital number, since it uses as much as digits as its factorization.

1301412141031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4948335400.

The product of its (nonzero) digits is 288, while the sum is 22.

The spelling of 1301412141031 in words is "one trillion, three hundred one billion, four hundred twelve million, one hundred forty-one thousand, thirty-one".