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130141300254013 is a prime number
BaseRepresentation
bin11101100101110011100001…
…111110001110010100111101
3122001210101102222100220201001
4131211303201332032110331
5114024213340331112023
61140442031000450301
736261253512100006
oct3545634176162475
9561711388326631
10130141300254013
1138515685242464
121271a30a179991
13578036c640949
14241cc303761ad
15100a41950a6ad
hex765ce1f8e53d

130141300254013 has 2 divisors, whose sum is σ = 130141300254014. Its totient is φ = 130141300254012.

The previous prime is 130141300254001. The next prime is 130141300254061. The reversal of 130141300254013 is 310452003141031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126568395068644 + 3572905185369 = 11250262^2 + 1890213^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130141300254013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130141300254083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070650127006 + 65070650127007.

It is an arithmetic number, because the mean of its divisors is an integer number (65070650127007).

Almost surely, 2130141300254013 is an apocalyptic number.

It is an amenable number.

130141300254013 is a deficient number, since it is larger than the sum of its proper divisors (1).

130141300254013 is an equidigital number, since it uses as much as digits as its factorization.

130141300254013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 130141300254013 its reverse (310452003141031), we get a palindrome (440593303395044).

The spelling of 130141300254013 in words is "one hundred thirty trillion, one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, thirteen".